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3x^2-16.5x+18=0
a = 3; b = -16.5; c = +18;
Δ = b2-4ac
Δ = -16.52-4·3·18
Δ = 56.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16.5)-\sqrt{56.25}}{2*3}=\frac{16.5-\sqrt{56.25}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16.5)+\sqrt{56.25}}{2*3}=\frac{16.5+\sqrt{56.25}}{6} $
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